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Home/ Questions/Q 941219
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T22:05:08+00:00 2026-05-15T22:05:08+00:00

I have a user model and a bid model. I want the user to

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I have a user model and a bid model. I want the user to know what their rank is based upon a score stored as a method, i.e. “3/7” based upon user.score method. Currently, I’m trying to tuck this geek_rank method into the Bid model as:

def user_rank(my_id)
  #Finds all bids associated with parent ticket object
  bids = Bid.find_by_ticket_id(self.ticket.id)
  bids = bids.sort_by { |b| b.user.score}
  i = 0
  for b in bids
    i += 1
    if b.user_id.to_i == my_id.to_i
      myrank = i
    end
  end
  user_rank = myrank.to_s + "/" + i.to_s
end

For some reason the sort_by method works in the controller but not when I try to sort in the model. Can anyone tell me what the problem is along with how my code sucks? 🙂

TO CLARIFY:

The actual error I’m getting is a method missing error.

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  1. Editorial Team
    Editorial Team
    2026-05-15T22:05:08+00:00Added an answer on May 15, 2026 at 10:05 pm

    The method find_by_ticket_id DOES not return an array; it returns a Bid.
    Use find_all_by_ticket_id instead.

    bids = Bid.find_all_by_ticket_id(self.ticket.id)
    bids = bids.sort_by { |b| b.user.score}
    

    I would rewrite your method as follows:

    def user_rank(my_id)
      # find the bid by the given id
      score = Bid.find_by_id(my_id).user.score
    
      # find the total number of bids for the ticket
      count  = Bid.count(:conditions => {:ticket_id => self.ticket.id})
    
      # find the rank
      rank   = Bid.count(:conditions => ["ticket_id =? AND users.score > ? ",
                  self.ticket.id, score], :joins => :user) + 1
      "#{rank}/#{count}"
    end
    

    In this approach most of the calculation is done by the DB.

    Caveat 1

    This method will return the same rank for people with the same score.

    E.g:

    #name #score   #rank
    foo        5        4
    bar        6        2
    kate       6        2
    kevin      8        1
    

    Caveat 2

    This solution performs better than your solution. But it still requires n * 3 round trips to the server to calculate the rank. Solution can be further optimized to calculate the rank of all the users in one SQL.

    Articles about rank calculation optimization:

    Article 1

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