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Home/ Questions/Q 7728517
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T05:44:16+00:00 2026-06-01T05:44:16+00:00

I have a value in my MS SQL table column called XDATA like this:

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I have a value in my MS SQL table column called “XDATA” like this:

<root><KV><Key>1</Key><Value>A</Value></KV>
    <KV><Key>2</Key><Value>B</Value></KV>
    <KV><Key>3</Key><Value>C</Value></KV></root>

I want to be able to get the value of the row back like this:

KEY, VALUE
1,A
2,B
3,C

So far I have written this:

DECLARE @a1  xml
    declare @x xml;
    set @x = '<root><KV><Key>1</Key><Value>A</Value></KV>
        <KV><Key>2</Key><Value>B</Value></KV>
        <KV><Key>3</Key><Value>C</Value></KV></root>';
   SELECT @a1 = @x.query('(/root/KV/Key/text())')
   select @a1

But I am getting 123 back. Not three rows with two columns. How do I get three rows back, each row with two columns:

KEY, VALUE
    1,A
    2,B
    3,C

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T05:44:17+00:00Added an answer on June 1, 2026 at 5:44 am

    Use nodes() to shred the XML to rows and use value() to get a value.

    select 
      T.N.value('Key[1]', 'int') as [Key],
      T.N.value('Value[1]', 'varchar(10)') as Value
    from @x.nodes('/root/KV') as T(N)
    
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