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Asked: 2026-05-29T17:16:40+00:00

I have a variable called $date with a date format like 2012-01-30. On the

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I have a variable called $date with a date format like 2012-01-30. On the other hand I have a field called srt_date_sortie in a mysql table. The format of that field is like 2012-01-30 11:31:00. I would like to select all records where $date and srt_date_sortie have equal dates not taking into consideration the time. Hope someone can help.

mysql_query("SELECT * FROM sorties WHERE srt_date_sortie = '$date'");

Here below how I build $date :

++$input;
$test=$input." days";
$date=date('Y-m-d', strtotime($test));

Thank you in advance for your replies. Cheers. Marc

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1 Answer

  1. Editorial Team

    For performance reasons you should avoid comparing against a derived column like DATE(srt_date_sortie) as this will prevent any indexes from being used. This negates a few of the solutions already posted.

    The most efficient way of querying against your DATETIME field is by using a range query like:

    mysql_query("SELECT * FROM sorties WHERE srt_date_sortie BETWEEN '$date 00:00:00' AND '$date 23:59:59'");

    Unless you need all of the rows from the table the SELECT * could be inefficient, just list the rows that you need to retrieve.

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