Question

I have a variable called root. The value for this variable is 0

$root = 0;

if($root == "readmore"){

            $root = 1701;
        }

somehow for some weird reason if $root is 0 it still enteres the if statement above? I have no idea what it could be

Answer 1

This is because, with type-juggling, 0 is considered equal to "readmore". You are asking PHP to compare a string to an integer, and it will interpret any string that doesn’t contain digits as a 0.

If you use if ($root === "readmore") ..., PHP will check the type as well as the value of the variable.