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Asked: 2026-05-13T19:38:56+00:00

I have a variable, start_time: (rdb:5) start_time.class ActiveSupport::TimeWithZone (rdb:5) start_time Tue, 23 Feb 2010

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I have a variable, start_time:

(rdb:5) start_time.class
ActiveSupport::TimeWithZone

(rdb:5) start_time
Tue, 23 Feb 2010 14:45:00 EST -05:00

(rdb:5) start_time.in_time_zone(ActiveSupport::TimeZone::ZONES_MAP["Pacific Time (US & Canada)"]).zone
"PST"

(rdb:5) start_time.in_time_zone(ActiveSupport::TimeZone::ZONES_MAP["Pacific Time (US & Canada)"]).to_s(:time)
"2:45 PM ET"

I’d like to change ‘to_s(:time)’ so that it outputs the time in whatever zone is specified in the variable, not the default system time. I.e. The output would be “11:45 AM PT”. How do I do this?

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1 Answer

  1. Editorial Team

    I ran into this issue recently and was able to solve it by essentially overriding the .to_s option that I was using. I created an initializer called time_formats.rb and added the following line to it. 

    Time::DATE_FORMATS[:time_in_zone] = "%H:%M %p"

    then changed (:time) to (:time_in_zone) like so…

    start_time.in_time_zone(...your timezone here...]).to_s(:time_in_zone)

    It should give you the time in the zone you are specifying. My environment is in UTC, so maybe that had something to do with it…

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