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Home/ Questions/Q 8564091
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T17:07:04+00:00 2026-06-11T17:07:04+00:00

I have a variable, textvar , that looks like this: type=1&name=bob type=2&name=sue I want

  • 0

I have a variable, textvar, that looks like this:

type=1&name=bob
type=2&name=sue

I want to create a new table that looks like this:

type  name
1     bob
2     sue

My approach is to use scan to split the variables on & so for the first observation I have

var1      var2
type=1    name=bob

So now I can use scan again to split on =:

vname = scan(var1, 1, '=');
value = scan(var1, 2, '=');

But how can I now assign value to the variable named vname?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T17:07:05+00:00Added an answer on June 11, 2026 at 5:07 pm

    PROC TRANPSOSE is the quickest way. You need an ID variable (dummy or real).

    data test;
    informat testvar $50.;
    input testvar $;
    datalines;
    type=1&name=bob
    type=2&name=sue
    ;;;;
    run;
    
    data test_vert;
    set test;
    id+1;
    length scanner $20 vname vvalue $20;
    scanner=scan(testvar,1,"&");
    do _t=2 by 1 until (scanner=' ');   
        vname=scan(scanner,1,"=");
        vvalue=scan(scanner,2,"=");
        output;
        scanner=scan(testvar,_t,"&");
    end;
    run;
    
    proc transpose data=test_vert out=test_T;
    by id;
    id vname;
    var vvalue;
    run;
    
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