Question

I have a variable type:

char (*p)[12] = calloc(n, sizeof(*p));

I need the variable to stay this way, but I am having trouble passing it as a parameter due to the function type giving me errors:

void myMethod(char *p) { ... }

What can I use in myMethod as the parameter to make this work?

Answer 1

Use the same type for the parameter as you did for the variable:

void myMethod(char (*p)[12])
{
  // do something with p
}
...
char (*p)[12] = calloc(n, sizeof *p);
myMethod(p);

Remember that p is a pointer to a 12-element array of char, not a simple pointer to char. Thus, the type of p[i] will be char [12] (which in most cases will decay to char *).