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Home/ Questions/Q 1898176
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T06:44:03+00:00 2026-05-17T06:44:03+00:00

I have a variable which holds a relative link for an image. This image

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I have a variable which holds a relative link for an image. This image link file name can have various lengths. For example…

/v/vspfiles/assets/images/d-amazingamethyst.jpg
/v/vspfiles/assets/images/cdacarbon.jpg  

I would like to extract from this variable only the filename with out the .jpg extention and without the preceeding path. So the first example above should return d-amazingamethyst

A Jquery answer is preferred but straight javascript is ok as well. Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-17T06:44:03+00:00Added an answer on May 17, 2026 at 6:44 am

    Methods on jsFiddle

    This returns “file-only.my”

    var x = "/v/whatever/file-only.my.jpg";
    x = x.substring(x.lastIndexOf("/")+1, x.lastIndexOf("."));
    

    It is going to get the substring, starting from the index of the last / plus 1 (the beggining of the filename) until the last index of the ., cutting the extension.

    You can also use the split function.

    var x = "/v/whatever/file-only.my.jpg";
    x = x.split("/");
    x = x[x.length-1].split('.');
    x.pop();
    x.join(".");
    

    But then you need to handle .s on the filename, if you cut by the index 0 it will get the wrong filename.

    I use .pop to remove the last element on the array, which is going to be the file extension, then I join everything back with .s.

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