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Home/ Questions/Q 644745
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:25:35+00:00 2026-05-13T21:25:35+00:00

I have a vector of pointers. I would like to call a function for

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I have a vector of pointers. I would like to call a function for every element, but that function takes a reference. Is there a simple way to dereference the elements?

Example:

MyClass::ReferenceFn( Element & e ) { ... }

MyClass::PointerFn( Element * e ) { ... }

MyClass::Function()
{
    std::vector< Element * > elements;
    // add some elements...

    // This works, as the argument is a pointer type
    std::for_each( elements.begin(), elements.end(),
                   boost::bind( &MyClass::PointerFn, boost::ref(*this), _1 ) );

    // This fails (compiler error), as the argument is a reference type
    std::for_each( elements.begin(), elements.end(),
                   boost::bind( &MyClass::ReferenceFn, boost::ref(*this), _1 ) );
}

I could create a dirty little wrapper that takes a pointer, but I figured there had to be a better way?

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:25:36+00:00Added an answer on May 13, 2026 at 9:25 pm

    You could use boost::indirect_iterator:

    std::for_each( boost::make_indirect_iterator(elements.begin()), 
                   boost::make_indirect_iterator(elements.end()),
                   boost::bind( &MyClass::ReferenceFn, boost::ref(*this), _1 ) );
    

    That will dereference the adapted iterator twice in its operator*.

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