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Home/ Questions/Q 8462243
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T14:06:48+00:00 2026-06-10T14:06:48+00:00

I have a very basic question ragarding Java generics . I thought that both

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I have a very basic question ragarding Java generics . I thought that both List<Number> and List<? extends Number> are homogeneous . Am I right or is there something fundamental I am missing ?

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  1. Editorial Team
    Editorial Team
    2026-06-10T14:06:49+00:00Added an answer on June 10, 2026 at 2:06 pm

    Generic types are more pedantic.

    <? extends Number> means Number or an unknown a sub class. If you obtain such a value it will be a Number, but you cannot give a value of this type because you don’t know which is valid.

    The difference is in arguments and return values.

    List<Number> numbers = new ArrayList<Number>();
    Number n = 1;
    numbers.add(n); // ok.
    n = numbers.get(0); // ok
    numbers.add(1); // ok.
    
    List<? extends Number> numbers2 = new ArrayList<Double>();
    numbers2.add(n); // not ok
    n = numbers2.get(0); // ok
    
    List<? super Number> numbers3 = new ArrayList<Serializable>();
    numbers3.add(n); // ok
    n = numbers3.get(0); // not ok.
    

    super is used in a few places to signify the type can be a super type. e.g.

    In Collections, this method says the Comparator needs to be able to compare the same type or any super type.

    public static <T> void sort(List<T> list, Comparator<? super T> c)
    

    This means you can have

    Comparator<Number> comparesAnyNumbers = ...
    List<Integer> ints = ...
    Collections.sort(ints, comparesAnyNumbers);
    
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