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Home/ Questions/Q 6120323
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:39:19+00:00 2026-05-23T15:39:19+00:00

I have a very frustrating problem which I cannot result. Its just not adding

  • 0

I have a very frustrating problem which I cannot result. Its just not adding up.

I am passing an array to process on a foreach() like so:

if (is_array($seminar)) {
foreach ($seminar as $sem_id)
    $sem_id_list .= "$sem_id";
    echo "$sem_id<br />";
}

As you can see my array() is $seminar, and that output looks like so:

Array
(
    [0] => 3
    [1] => 8
    [2] => 9
    [3] => 13
    [4] => 14
    [5] => 15
)

As you can see in my code, I am building a block w/ =. like: *$sem_id_list .= “$sem_id”;* and the when echoed out looks like: 389131415 as expected.

BUT when I simply trying to iterate through and print each value like: *echo “$sem_id
“;* I only get the last array() item!!

I’ve never run into this problem before. I am guessing I am missing something dead simple here, but from all my experience this should be working and printing those results just fine.

As a side note, var_dump($seminar); produces this too:

array(6) { [0]=> string(1) "3" [1]=> string(1) "8" [2]=> string(1) "9" [3]=> string(2) "13" [4]=> string(2) "14" [5]=> string(2) "15" }
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  1. Editorial Team
    Editorial Team
    2026-05-23T15:39:19+00:00Added an answer on May 23, 2026 at 3:39 pm

    You’re missing the opening brace of the foreach and a closing brace. Try:

    if (is_array($seminar)) {
      foreach ($seminar as $sem_id) {
        $sem_id_list .= "$sem_id";
        echo "$sem_id<br />";
      }
    }
    

    or build the list and print it at the end:

    if (is_array($seminar)) {
      foreach ($seminar as $sem_id) {
        $sem_id_list .= "$sem_id";
      }
      echo "$sem_id_list";
    }
    
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