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Home/ Questions/Q 862871
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T09:12:52+00:00 2026-05-15T09:12:52+00:00

I have a very large text file and I need to gather data from

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I have a very large text file and I need to gather data from somewhere near the end. Maybe Scanner isn’t the best way to do this but it would be very wasteful to start at the top and grab 6000 lines before getting to the part of the file I am interested in. Is there a way to either tell Scanner to jump to say 7/8ths down the document or start from the bottom and scan upwards grabbing line by line?

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  1. Editorial Team
    Editorial Team
    2026-05-15T09:12:53+00:00Added an answer on May 15, 2026 at 9:12 am

    The underlying input source for a java.util.Scanner is a java.lang.Readable. Beyond the Scanner(File) constructor, a Scanner neither knows nor cares of the fact that it’s scanning a file.

    Also, since it’s regex based on java.util.regex.*, there’s no way it can scan backward.

    To accomplish what you want to do, it’s best to do it at the input source level, e.g. by using InputStream.skip of the source before passing it to the constructor of Scanner.


    On Scanner.skip

    Scanner itself does have a skip, and a pattern like "(?s).{10}" would skip 10 characters (in (?s) single-line/Pattern.DOTALL mode), but this is perhaps a rather roundabout way of doing it.

    Here’s an example of using skip to skip a given number of lines.

        String text =
            "Line1 blah blah\n" +
            "Line2 more blah blah\n" +
            "Line3 let's try something new \r\n" +
            "Line4 meh\n" + 
            "Line5 bleh\n" + 
            "Line6 bloop\n";
        Scanner sc = new Scanner(text).skip("(?:.*\\r?\\n|\\r){4}");
        while (sc.hasNextLine()) {
            System.out.println(sc.nextLine());
        }
    

    This prints (as seen on ideone.com):

    Line5 bleh
    Line6 bloop
    
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