Question

I have a very large text file which contains data similar to the following:

     but/CC as/IN 1/Z church/NP historian/NN/Fc 
     as/IN 1/Z "/Fe rupture/NN and/CC new/JJ beginning/NN century/NN ./Fp
    ======>match found: \#\#[a-z]+\/NN\#\#
    ======>match found: be\/V[A-Z]+(\s[.]{0,10})?\#\#
    ======>match found: \#\#\sof\/IN

I would like to use the (linux) terminal command grep to match and erase all the lines that start with:

======>match found:

and end with a newline character.

Thus, according to the previous example, I’d like to run grep and obtain the following output

but/CC as/IN 1/Z church/NP historian/NN/Fc
as/IN 1/Z “/Fe rupture/NN and/CC new/JJ beginning/NN century/NN ./Fp

Thank you in advance for your help

Answer 1

grep -E -v '^======>match found:.+$' file.txt

-E turns on extended regular expressions, and -v negates the output, i.e. prints all lines that don’t match.