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Home/ Questions/Q 7674731
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T16:48:15+00:00 2026-05-31T16:48:15+00:00

I have a very simple code, which annoyingly was working and for the life

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I have a very simple code, which annoyingly was working and for the life of me I can not see why it is now failing:

function imageSize(img){
  var theImage = new Image();
  theImage.src = img.attr('src');
  var imgwidth = theImage.width;
  var imgheight = theImage.height;

  alert(imgwidth+'-'+imgheight);
}

The “img” variable being passed is the img object, obtained from:

jQuery('img')
.each(function(){
    var imgsrc = jQuery(this);
    imageSize(imgsrc);
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T16:48:16+00:00Added an answer on May 31, 2026 at 4:48 pm

    The image may not have loaded yet. So, try (untested):

    function imageSize(img){
      var theImage = new Image();
      $(theImage).load(function() {
        var imgwidth = this.width;
        var imgheight = this.height;
    
        alert(imgwidth+'-'+imgheight);
      });
      theImage.src = img.attr('src');
    }
    
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