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Home/ Questions/Q 5996513
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T00:06:50+00:00 2026-05-23T00:06:50+00:00

I have a very simple Java JTable question. I am creating this class to

  • 0

I have a very simple Java JTable question.
I am creating this class to make things easier in the rest of my application. I receive an error when running it. I know what the errors mean, but have no idea what else to try.

You’ll see in the code what I am trying to accomplish:

My Class:

import javax.swing.*;
public class CPTable extends JScrollPane
{
    private JTable table;
    CPTable(Object [] headers, Object [][] data)
    {
        table = new JTable(data, headers);
        this = new JScrollPane(table);//The line I can't figure out.
    }
}

My errors: (an obvious one)

cannot assign a value to final variable this
    this = new JScrollPane(table);

and

incompatible types
found   : javax.swing.JScrollPane
required: CPTable
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:06:51+00:00Added an answer on May 23, 2026 at 12:06 am

    Try this:

    private CPTable(JTable table) {
        super(table);
        this.table = table;
    }
    
    public CPTable(Object[] headers, Object[][] data) {
        this(new JTable(data, headers));
    }
    

    You cannot reassign this, but you can cause the correct superclass constructor to be called by using super (which must be the first statement in your constructor).

    The this statement is called “constructor delegation”—it chains through to the other constructor so that you can pass the table to the superclass as well as assign it to your table field.

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