Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4034274
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T11:57:06+00:00 2026-05-20T11:57:06+00:00

I have a very simple test page that tests jquery (1.4.2) queue and delay.

  • 0

I have a very simple test page that tests jquery (1.4.2) queue and delay.

    for (var i = 1; i <= 5; i++) {
        $('#test')
        //.delay(50)
        .queue(function(next) {
            console.log(i);
            next();
        });
    }

Now when I run this code in FF with firebug, I get what I expected, 1 ~ 5.

However, if I un-comment delay, I got 6 five times instead?

Can someone please help me clarify this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-20T11:57:07+00:00Added an answer on May 20, 2026 at 11:57 am

    The i is a single variable stored one time and shared by all iterations of the loop. Without the .delay() you’re using the value of i right then, so it’s what you expect. With the .delay() however, you’re using what the value is later…and later it’s what it ended up as at the end of the loop, 6.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a very simple test page that uses XHR requests with jQuery's $.getJSON
I have a very simple test with jQuery and a django view: HTML -
I have recorded a very simple test case Using the Selenium IDE integrated with
I have a very simple question. I want to test whether a particular port
i have very simple problem. I need to create model, that represent element of
I have a very simple bit of script that changes the status of an
I have a very simple Java RMI Server that looks like the following: import
I have a simple page that contains an iframe. The iframe contains a page
I have a very simple mod_wsgi python application that tries to write to a
I have a simple page for a chat system. Test page can be found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.