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Home/ Questions/Q 5948991
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T17:11:12+00:00 2026-05-22T17:11:12+00:00

I have a very very simple bit of code in my (test) Chrome extension:

  • 0

I have a very very simple bit of code in my (test) Chrome extension:

    function test()
    {
    alert("In test!");
    }

   chrome.tabs.onUpdated.addListener(function(tabid, changeinfo, tab) {
    var url = tab.url;
        if (url !== undefined) {

        test();
    }
   });

My question is, why is test() firing twice? And more importantly, how do I make it fire just once?

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  1. Editorial Team
    Editorial Team
    2026-05-22T17:11:13+00:00Added an answer on May 22, 2026 at 5:11 pm

    Have a look at what the different states are when the event is dispatched. I presume, that it is getting dispatched once when the state is “loading” or when the state is “complete”. If that is the case, then your problem would be fixed with:

     function test()
        {
        alert("In test!");
        }
    
       chrome.tabs.onUpdated.addListener(function(tabid, changeinfo, tab) {
        var url = tab.url;
            if (url !== undefined && changeinfo.status == "complete") {
    
            test();
        }
       });
    
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