Question

I have a view in django that can accept a number of different filter parameters, but they are all optional. If I have 6 optional filters, do I really have to write urls for every combination of the 6 or is there a way to define what parts of the url are optional?

To give you an example with just 2 filters, I could have all of these url possibilities:

/<city>/<state>/
/<city>/<state>/radius/<miles>/
/<city>/<state>/company/<company-name>/
/<city>/<state>/radius/<miles>/company/<company-name>/
/<city>/<state>/company/<company-name>/radius/<miles>/

All of these url’s are pointing to the same view and the only required params are city and state. With 6 filters, this becomes unmanageable.

What’s the best way to go about doing what I want to achieve?

Answer 1

One method would be to make the regular expression read all the given filters as a single string, and then split them up into individual values in the view.

I came up with the following URL:

(r'^(?P<city>[^/]+)/(?P<state>[^/]+)(?P<filters>(?:/[^/]+/[^/]+)*)/?$',
 'views.my_view'),

Matching the required city and state is easy. The filters part is a bit more complicated. The inner part – (?:/[^/]+/[^/]+)* – matches filters given in the form /name/value. However, the * quantifier (like all Python regular expression quantifiers) only returns the last match found – so if the url was /radius/80/company/mycompany/ only company/mycompany would be stored. Instead, we tell it not to capture the individual values (the ?: at the start), and put it inside a capturing block which will store all filter values as a single string.

The view logic is fairly straightforward. Note that the regular expression will only match pairs of filters – so /company/mycompany/radius/ will not be matched. This means we can safely assume we have pairs of values. The view I tested this with is as follows:

def my_view(request, city, state, filters):
    # Split into a list ['name', 'value', 'name', 'value']. Note we remove the
    # first character of the string as it will be a slash.
    split = filters[1:].split('/')

    # Map into a dictionary {'name': 'value', 'name': 'value'}.
    filters = dict(zip(split[::2], split[1::2]))

    # Get the values you want - the second parameter is the default if none was
    # given in the URL. Note all entries in the dictionary are strings at this
    # point, so you will have to convert to the appropriate types if desired.
    radius = filters.get('radius', None)
    company = filters.get('company', None)

    # Then use the values as desired in your view.
    context = {
        'city': city,
        'state': state,
        'radius': radius,
        'company': company,
    }
    return render_to_response('my_view.html', context)

Two things to note about this. First, it allows unknown filter entries into your view. For example, /fakefilter/somevalue is valid. The view code above ignores these, but you probably want to report an error to the user. If so, alter the code getting the values to

radius = filters.pop('radius', None)
company = filters.pop('company', None)

Any entries remaining in the filters dictionary are unknown values about which you can complain.

Second, if the user repeats a filter, the last value will be used. For example, /radius/80/radius/50 will set the radius to 50. If you want to detect this, you will need to scan the list of values before it is converted to a dictionary:

given = set()
for name in split[::2]:
    if name in given:
        # Repeated entry, complain to user or something.
    else:
        given.add(name)