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Home/ Questions/Q 348949
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:24:45+00:00 2026-05-12T11:24:45+00:00

I have a view that takes data from my site and then makes it

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I have a view that takes data from my site and then makes it into a zip compressed csv file. Here is my working code sans zip:

def backup_to_csv(request):
    response = HttpResponse(mimetype='text/csv')
    response['Content-Disposition'] = 'attachment; filename=backup.csv'

    writer = csv.writer(response, dialect='excel')

    #code for writing csv file go here...

    return response

and it works great. Now I want that file to be compressed before it gets sent out. This is where I get stuck.

def backup_to_csv(request):

    output = StringIO.StringIO() ## temp output file
    writer = csv.writer(output, dialect='excel')

    #code for writing csv file go here...

    response = HttpResponse(mimetype='application/zip')
    response['Content-Disposition'] = 'attachment; filename=backup.csv.zip'

    z = zipfile.ZipFile(response,'w')   ## write zip to response
    z.writestr("filename.csv", output)  ## write csv file to zip

    return response

But thats not it and I have no idea how to do this.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:24:45+00:00Added an answer on May 12, 2026 at 11:24 am

    OK I got it. Here is my new function:

    def backup_to_csv(request):
    
        output = StringIO.StringIO() ## temp output file
        writer = csv.writer(output, dialect='excel')
    
        #code for writing csv file go here...
    
        response = HttpResponse(mimetype='application/zip')
        response['Content-Disposition'] = 'attachment; filename=backup.csv.zip'
    
        z = zipfile.ZipFile(response,'w')   ## write zip to response
        z.writestr("filename.csv", output.getvalue())  ## write csv file to zip
    
        return response
    
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