Question

I have a Visual Studio 2008 C++ application where I would like to copy all of program arguments in to a string separated by a whitespace ” “. i.e., if my program is called as foo.exe \Program Files, then my folder string below would contain \Program Files

Below is an example of what I’m doing now. I was wondering if there was a shorter or easier method of doing this. Is there an easy way to eliminate the std::wstringstream variable?

int _tmain( int argc, _TCHAR* argv[] )
{
    std::wstringstream f;
    std::copy( argv + 1,
               argv + argc,
               std::ostream_iterator< std::wstring, wchar_t >( f, L" " ) );
    std::wstring folder = f.str();

    // ensure the folder begins with a backslash
    if( folder[ 0 ] != L'\\' )
        folder.insert( 0, 1, L'\\' );

    // remove the trailing " " character from the end added by the std::copy() above
    if( *folder.rbegin() == L' ')
        folder.erase( folder.size() - 1 );

    // ... 
}

Thanks,
PaulH

Answer 1

How about this:

int main(int argc, char* argv[])
{
    std::string path;
    if(argc < 2)
    {
        std::cout << "Not enough arguments" << std::endl;
        return;
    }
    path = argv[1]; // Assignment works from char* types
    // Do the rest of your folder manipulation below here
}

That should work. Even with the main() function declared as it is now, it should still work from a TCHAR (I think), or you can change main’s declaration to a more “standard” main() declaration.