Question

I have a web application built on JSF with MySQL as DB. I have already implemented the code to prevent CSRF in my application.

Now since my underlying framework is JSF, I guess I don’t have to handle XSS attack as it is already handled by UIComponent. I am not using any JavaScript in any of the view pages. Even if I use do I really need to implement code to prevent XSS attacks?

For DB we are using prepared statements and stored procedures in all DB interactions.

Is there anything else needs to be handled for preventing these 3 common attacks?
I have already been through the OWASP site and their cheat sheets.

Do I need to take care of any other potential attack vectors?

Answer 1

XSS

JSF is designed to have builtin XSS prevention. You can safely redisplay all user-controlled input (request headers (including cookies!), request parameters (also the ones which are saved in DB!) and request bodies (uploaded text files, etc)) using any JSF component.

<h:outputText value="#{user.name}" />
<h:outputText value="#{user.name}" escape="true" />
<h:inputText value="#{user.name}" />
etc...

Note that when you’re using JSF 2.0 on Facelets, then you can use EL in template text like so:

<p>Welcome, #{user.name}</p>

This will also implicitly be escaped. You don’t necessarily need <h:outputText> here.

Only when you’re explicitly unescaping user-controlled input using escape="false":

<h:outputText value="#{user.name}" escape="false" />

then you’ve a potential XSS attack hole!

If you’d like to redisplay user-controlled input as HTML wherein you would like to allow only a specific subset of HTML tags like <b>, <i>, <u>, etc, then you need to sanitize the input by a whitelist. The HTML parser Jsoup is very helpful in this.

itemLabelEscaped bug in Mojarra < 2.2.6

Older Mojarra versions before 2.2.6 had the bug wherein <f:selectItems itemLabel> incorrectly renders the label unescaped when provided a List<T> via <f:selectItems var> instead of List<SelectItem> or SelectItem[] as value (issue 3143). In other words, if you’re redisplaying user-controlled data as item labels via a List<T>, then you’ve a potential XSS hole. If upgrading to at least Mojarra 2.2.6 is not an option, then you need to explicitly set itemLabelEscaped attribute to true to prevent that.

<f:selectItems value="#{bean.entities}" var="entity" itemValue="#{entity}"
    itemLabel="#{entity.someUserControlledProperty}" itemLabelEscaped="true" />

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CSRF

JSF 2.x has already builtin CSRF prevention in flavor of javax.faces.ViewState hidden field in the form when using server side state saving. In JSF 1.x this value was namely pretty weak and too easy predictable (it was actually never intended as CSRF prevention). In JSF 2.0 this has been improved by using a long and strong autogenerated value instead of a rather predictable sequence value and thus making it a robust CSRF prevention.

In JSF 2.2 this is even be further improved by making it a required part of the JSF specification, along with a configurable AES key to encrypt the client side state, in case client side state saving is enabled. See also JSF spec issue 869 and Reusing ViewState value in other session (CSRF). New in JSF 2.2 is CSRF protection on GET requests by <protected-views>.

Only when you’re using stateless views as in <f:view transient="true">, or there’s somewhere a XSS attack hole in the application, then you’ve a potential CSRF attack hole.

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SQL injection

This is not JSF’s responsibility. How to prevent this depends on the persistence API you’re using (raw JDBC, modern JPA or good ol’ Hibernate), but all boils down that you should never concatenate user-controlled input into SQL strings like so

String sql = "SELECT * FROM user WHERE username = '" + username + "' AND password = md5(" + password + ")";
String jpql = "SELECT u FROM User u WHERE u.username = '" + username + "' AND u.password = md5('" + password + "')";

Imagine what would happen if the enduser chooses the following name:

x'; DROP TABLE user; --

You should always use parameterized queries where applicable.

String sql = "SELECT * FROM user WHERE username = ? AND password = md5(?)";
String jpql = "SELECT u FROM User u WHERE u.username = ?1 AND u.password = md5(?2)";

In plain JDBC you need to use PreparedStatement to fill the parameter values and in JPA (and Hibernate), the Query object offers setters for this as well.