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Home/ Questions/Q 9140819
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T09:33:58+00:00 2026-06-17T09:33:58+00:00

I have a web form as <asp:TextBox ID=txtname runat=server Text=Post on Next Page/> <asp:Button

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I have a web form as

<asp:TextBox ID="txtname" runat="server" Text="Post on Next Page"/>
<asp:Button ID="btn1" runat="server" PostBackUrl="~/Page2.aspx" Text="Post on next page" />

Now on Page2.aspx the code-behind is as follows:

protected void Page_Load(object sender, EventArgs e)
{
   if(PreviousPage!=null && PreviousPage.IsCrossPagePostBack)
   {
       TextBox txt1 = (TextBox)PreviousPage.FindControl("txtname");
       label1.Text = "Value: " + txt1.Text;
   }
}

I end up getting the error object reference not set to instance of an object for txt1

Where label1 is a label used to display the output. However, the value is not displayed.

What step am i missing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T09:33:59+00:00Added an answer on June 17, 2026 at 9:33 am

    Try this

    if (PreviousPage != null && PreviousPage.IsCrossPagePostBack)
                {
                    //get the content place holder from master page of your previous page where your controls are placed
                    //In this code the txtname textbox is placed inside ContentPlaceHolderID="MainContent"
                    var cp =PreviousPage.Master.FindControl("MainContent") as ContentPlaceHolder;
                    //find the textbox inside content place holder from previous page
                    TextBox txt1 = cp.FindControl("txtname") as TextBox;
                    label1.Text = "Value: " + txt1.Text;
                }
    
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