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Home/ Questions/Q 8996621
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:46:44+00:00 2026-06-15T23:46:44+00:00

I have a webgrid via this code @grid.GetHtml( tableStyle: webgrid, columns: grid.Columns( grid.Column(header: Link,

  • 0

I have a webgrid via this code

@grid.GetHtml(
                        tableStyle: "webgrid",
                        columns: grid.Columns(
                        grid.Column(header: "Link", style: "labelcolumn", format: (item) => Html.ActionLink("Edit Item", "EditQueue", new { id = item.QueueID})),
                        grid.Column("Description", "Description"),
                        grid.Column("QueueDate", "QueueDate"),
                        grid.Column("Note", "Note"),
                        grid.Column("Status", "Status"),
                        grid.Column("LastUpdated", "LastUpdated")
                            )
                    )

I created a test case with ID 1. I then click the link in the first column. I get a 404 error because I haven’t created a page for this at /Home/EditQueue/1

However I obviously don’t want to create a page for each number. What is the best practice to create a page that just displays the ID I passed into it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T23:46:45+00:00Added an answer on June 15, 2026 at 11:46 pm

    Create an action method which accepts the id as parameter, in your HomeController

    public ActionResult EditQueue(int id)
    {
        //Get the details of queue using id and return a view.
        return View();
    }
    

    You probably want to show the data to edit. so get the data using the id and return that.

    public ActionResult EditQueue(int id)
    {
        //Get the details of queue using id and return a view.
        Queue queue=repositary.GetQueueFromID(id);
        return View(queue);
    }
    

    Assuming repositary.GetQueueFromID method will return a Queue class object and your View (Edit.cshtml) is strongly typed to that.

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