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Home/ Questions/Q 601549
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:43:39+00:00 2026-05-13T16:43:39+00:00

I have a weighted graph with its nodes and edges. Each node contains a

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I have a weighted graph with its nodes and edges.

Each node contains a LinkedList called edges that stores the edges of this node. Each edge has an weight and a node (node at the other end).

I already did this:

static void removeEdge(Node n1, Node n2)
{
     n1.edges.Remove(n1.edges.First(a => a.node == n2));
     n2.edges.Remove(n2.edges.First(a => a.node == n1));
}

I am trying to do an updateEdge method, that would take that same lambda expression and then do this:

(a => a.node == n2).weight = otherValue;

but I am getting an error. Isn’t this allowed? Or am I doing something wrong? From what I’ve tested the lambda expression seems ok as far as removing the elements, though I’m new at this so I’m pretty lost tbh.

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:43:39+00:00Added an answer on May 13, 2026 at 4:43 pm

    I think you’re misunderstanding what a lambda is. When you say something like

    ...First(x => x.bar == 10)
    

    what happens is we generate something like this:

    static bool M(X x) { return x.bar == 10; }
    ...
    ...  First(new Func<X, bool>( M ) )
    

    That is, we make a method out of the lambda, and then make a delegate out of the method, and then pass the delegate.

    Doing something like

    (x=>x.bar==10).foo = whatever
    

    is morally the same as doing something like M.foo = whatever, where M is a method. Methods don’t have properties, so this is always illegal. Similarly, lambdas don’t have properties either. A lambda is just a convenient syntax for a method.

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