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Home/ Questions/Q 6648271
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:38:09+00:00 2026-05-26T00:38:09+00:00

I have a while loop here that only takes in 1 and 2 as

  • 0

I have a while loop here that only takes in 1 and 2 as the number, if i insert and number that is not these my else statement will keep asking for the correct one, which works correctly. But if i insert a letter my else statement loops forever. How can i fix this?

#include <iostream>
using namespace std;

int main()
{
int myChoice;
cin >> myChoice;

while ( myChoice >= 2 ||  myChoice <= 1)
{
    if (myChoice == 1)
    {
        cout <<"food1";
        break;
    }
    else if (myChoice == 2)
    {
        cout <<"food2";
        break;
    }
    else
    {
        cout << " " << endl;
        cout << "Please select the proper choices" << endl;
        cout << "Try again: ";
        cin >> myChoice;
    }
}
return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:38:10+00:00Added an answer on May 26, 2026 at 12:38 am

    If you enter a non-number, then cin >> myChoice fails. That means that it leaves the input intact in the input buffer and when you get there again it tries to parse it and fails, and so on… You must clear the error state and ignore the non-digits. The simplest way is something like this:

    cout << "Try again: ";
    cin.clear(); // clear error state
    cin.ignore(std::numeric_limits<streamsize>::max(), '\n'); // ignore till the end of line
    cin >> myChoice;
    
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