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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:30:53+00:00 2026-06-14T21:30:53+00:00

I have a while loop that scans in an input set of integers. It

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I have a while loop that scans in an input set of integers. It scans and prints all of the numbers with “…” at the end and skips to the next line. However, the script does not: execute past the while loop and print TEST.

For example, I enter:
3 44 62 1

It prints:
3…

44…

62…

1…

When it should print:
3…

44…

62…

1…

TEST

while(scanf("%d", &n) != -1) {
    x[i] = n;
    i++;

    printf("%d", n);
    printf("...\n");
}

printf("TEST");

What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-06-14T21:30:54+00:00Added an answer on June 14, 2026 at 9:30 pm
    1. scanf("%d", &n) != 1 is wrong. It should be scanf("%d", &n) == 1.
    2. You’re expecting the loop to end just because you hit enter? As written, your program will only stop if scanf fails to read a number due to reaching the end of the input file. If you’re on Unix, you can signal EOF from the terminal by hitting Ctrl-D. If you’re on Windows, it’s Ctrl-Z Enter. (Also, don’t rely on EOF being -1; it’s not portable.)
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