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Home/ Questions/Q 8119389
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T04:47:26+00:00 2026-06-06T04:47:26+00:00

I have a worker method with an optional parameter Work(string input = DefaultInput) {

  • 0

I have a worker method with an optional parameter

Work(string input = DefaultInput)
{
    //do stuff
}

And I have a wrapper around this, which also take the string input, but this can also be optional…

WorkWrapper(int someParameter, string input = DefaultInput)
{
    //do initialization
    Work(input);

}

The problem here is I duplicate reference to DefaultInput, if, say, I change the default input of work to NewDefaultInput, I will need to update the workWrapper as well, otherwise it will still use the old default.

Is there a way so that the default input do not need to be declared twice? Possibly without having two overloads for workwrapper..

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T04:47:28+00:00Added an answer on June 6, 2026 at 4:47 am

    If you want the defaults to be in sync between the two methods, you really don’t need the default in the wrapper, right?

    public void Work(string input = DefaultInput)
    {
        //do stuff
    }
    

    …

    public void WorkWrapper(int someParameter, string inputOverride = null)
    {
        //do initialization
    
        if (inputOverride == null) Work();
        else Work(inputOverride);    
    }
    

    If they are in the same class/hierarchy, you could also just declare a const to ensure that the defaults remain the same.

    private const string DEFAULT_INPUT = "Default Input"; // protected if in base class
    
    public void Work(string input = DEFAULT_INPUT)
    {
        //do stuff
    }
    
    public void WorkWrapper(int someParameter, string input = DEFAULT_INPUT)
    {
        //do initialization
        Work(input);    
    }
    
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