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Home/ Questions/Q 398031
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:42:29+00:00 2026-05-12T16:42:29+00:00

I have a worker thread, which holds a list of ‘Thread Actions’, and works

  • 0

I have a worker thread, which holds a list of ‘Thread Actions’, and works through them as an when.

template <class T> class ThreadAction
{
public:

  typedef void (T::*action)();

  ThreadAction(T* t, action f) :
    func(f),obj(t) {}
  void operator()() { (obj->*func)(); }

  void (T::*func)();
  T* obj;

};

It’s normally called like this

myActionThread->addAction(
    new ThreadAction<TheirClass>(this, &TheirClass::enable)
);

Which worked fine until

 void TheirClass::enable()

was changed to

 bool TheirClass::enable()

Sadly we can’t change it back again because other stuff needs the new format, (and overloads can’t differ by return type alone).

I did try

myActionThread->addAction( 
    new ThreadAction<TheirClass>(this, 
        reinterpret_cast<void(TheirClass::*)>(&TheirClass::enable)
    )
);

Which appears to work just fine, but I’m not certain that reinterpreting a function pointer like this is ‘defined’ behaviour, can somebody please advise?

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:42:30+00:00Added an answer on May 12, 2026 at 4:42 pm

    This is definitely not supported behavior, and can potentially cause your program to crash.

    Basically, you need to make a wrapper for TheirClass::enable() that will have the proper return type. A simple one-liner will suffice:

    public:
        void enableWrapper() { enable(); };
    

    Then call:

    myActionThread->addAction(
        new ThreadAction<TheirClass>(this, &TheirClass::enableWrapper)
    );
    

    If you can’t modify TheirClass directly, then create a simple subclass or helper class that implements the wrapper.

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