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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T09:15:09+00:00 2026-05-15T09:15:09+00:00

I have a WPF application in which I have a hook at PreviewTextInput, through

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I have a WPF application in which I have a hook at PreviewTextInput, through that I get the currently entered character and I have the string already entered. Given this I need to write the following function :

bool ShouldAccept(char newChar,string existingText)

existingText can be comma seperated valid numbers(including exponential) and it should just return false when invalid characters are pressed.

My code(if else based) currently has a lot of flaws, I wanted to know if there is any smart way to do it.

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  1. Editorial Team
    Editorial Team
    2026-05-15T09:15:10+00:00Added an answer on May 15, 2026 at 9:15 am

    I finally did it using Regex,

    private readonly List<Regex> ValidNumberRegex = new List<Regex>
                                    {
                                        new Regex(@"^-?$"),
                                        new Regex(@"^-?\d+$"),
                                        new Regex(@"^-?\d+\.$"),
                                        new Regex(@"^-?\d+\.\d+$"),
                                        new Regex(@"^-?\d+\.\d+[eE]$"),
                                        new Regex(@"^-?\d+\.\d+[eE]-?$"),
                                        new Regex(@"^-?\d+\.\d+[eE]-?\d+$"),
                                        new Regex(@"^-?\d+[eE]-?$"),
                                        new Regex(@"^-?\d+[eE]-?\d+$"),
                                    };
    

    So basically my ShouldAccept looks like this :

    1. If the input is the first character then only allow “-” or 0-9
    2. Else if input is “,” then split existingText by “,” and validate all existing numbers
    3. For all other input, figure out the current number (it can be an edit of existing number or continuation of last number), after figuring it out, validate the number with newchar

    In all its just 50 lines of code. I could have combined all the regex but this is much easier to read.

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