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Home/ Questions/Q 6345935
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T20:55:10+00:00 2026-05-24T20:55:10+00:00

I have a WPF application, where I make a long-running WCF call using the

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I have a WPF application, where I make a long-running WCF call using the System.Threading.Tasks. I catch unhandled exceptions by adding a handler to Application.Current.DispatcherUnhandledException.

I create a task, where the ContinueWith function runs on the UI thread using the following code:

var task = new Task<T>(func).ContinueWith(t =>
{
    if (t.IsFaulted)
    {
        throw t.Exception.GetBaseException();
    }
    else
    {
        // Show t.Result on UI
    }
}, TaskScheduler.FromCurrentSynchronizationContext());

When an exception occurs in the task, I would like to rethrow the exception so that the DispatcherUnhandledException handler can handle it. But when I rethrow the exception, as shown above, it crashes my app and the DispatcherUnhandledException is not invoked.

How do I rethrow the exception on the UI thread so that the DispatcherUnhandledException handler is invoked?

When I was using the BackgroundWorker, rethrowing the exception did exactly this. Basically, I am looking to replace BackgroundWorker with Task, since Task has some really nice features I would like to take advantage of.

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  1. Editorial Team
    Editorial Team
    2026-05-24T20:55:11+00:00Added an answer on May 24, 2026 at 8:55 pm

    One way to solve this, is by rethrowing the Exception in a Lambda expression contained within the statement. Something like:

    Exception ex = t.Exception;
    Dispatcher.CurrentDispatcher.BeginInvoke(new Action(() => { throw ex; }));
    

    I don’t recommend that though as it is a bit foul, but it does answer the question!

    You could alternatively do something similarly as nasty with SynchronizationContext.Post.

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