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Home/ Questions/Q 3931016
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T23:18:43+00:00 2026-05-19T23:18:43+00:00

I have a wpf-mvvm application. I have an observable collection in my viewmodel public

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I have a wpf-mvvm application.

I have an observable collection in my viewmodel

public ObservableCollection<BatchImportResultMessageDto> ImportMessageList { get; set; } 

“BatchImportResultMessageDto” contains two properties..

result type..and message. Result type can be success or failure.

I need to display success in one list box ..and failure in another listbox.

I can do this..by having 2 observable collections in viewmodel to hold success/failure.

public ObservableCollection<BatchImportResultMessageDto> ImportFailureMessageList { get; set; } // To hold the failure messages.
public ObservableCollection<BatchImportResultMessageDto> ImportSuccessMessageList { get; set; } // To hold the sucess messages.

But is there any other better way so that i can filter it (without new two collections) ?

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  1. Editorial Team
    Editorial Team
    2026-05-19T23:18:44+00:00Added an answer on May 19, 2026 at 11:18 pm

    You can use a CollectionViewSource and make it a property of your view model, and bind to that instead of your ImportMessageList collection directly from the XAML. Set your ImportMessageList collection as the Source of the CollectionViewSource, and then configure a predicate to do your filtering on the CollectionViewSource.

    Something like:

    private ICollectionView messageListView;
    public ICollectionView MessageListView
    {
        get { return this.messageListView; }
        private set
        {
          if (value == this.messageListView)
          {
            return;
          }
    
          this.messageListView = value;
          this.NotifyOfPropertyChange(() => this.MessageListView);
        }
    }
    
    ...
    
    
    this.MessageListView = CollectionViewSource.GetDefaultView(this.ImportMessageList);
    this.MessageListView.Filter = new Predicate<object>(this.FilterMessageList);
    
    ...
    
    public bool FilterMessageList(object item)
    {
      // inspect item as message here, and return true 
      // for that object instance to include it, false otherwise
      return true;
    }
    
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