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Home/ Questions/Q 6883051
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T05:19:59+00:00 2026-05-27T05:19:59+00:00

I have a xml file like this <Document> <Tests> <Test> <Name>A</Name> <Type>Like A</Type> <Members>

  • 0

I have a xml file like this

<Document>
   <Tests>
       <Test>
          <Name>A</Name>
          <Type>Like A</Type>
          <Members>
               <Member>1</Member>
               <Member>2</Member>
               <Member>3</Member>
          </Members>
       </Test>
       <Test>
          <Name>B</Name>
          <Type>Like B</Type>
          <Members>
               <Member>4</Member>
               <Member>5</Member>
               <Member>6</Member>
          </Members>
       </Test>
    </Tests>
</Document>

Now I made a class to hold data for each Test nodes:

public class TestData
{
public string Name {get;set;}
public string Type {get;set;}

public List<string> Members = new List<string>();

public AddMembers(List<string> members)
{
Members.AddRange(members);
}
}

Now I am trying to use xpath to fill my TestData class, but I have problem adding members to the List I have. I am trying to use LINQ but I cant do it yet 🙁

   public List<TestClass> GetTests()
    {
        List<TestClass> tests = new List<TestClass>();
        TestClass test;

        XPathNodeIterator it = nav.Select("/Document/Tests/Test");

        foreach (XPathNavigator val in it)
        {
            test= new TestClass();
            test.Name = val.SelectSingleNode(nav.Compile("Name")).Value;
            test.Type = val.SelectSingleNode(nav.Compile("Type")).Value;
            test.AddMembers(); //How can I return all the member nodes in a list?

            tests.Add(test);
        }


        return tests ;
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T05:20:00+00:00Added an answer on May 27, 2026 at 5:20 am

    It’s not clear why you’re using XPathNodeIterator to start with, to be honest. If you can use LINQ to XML for this, it’s really simple:

    var list =  doc.Descendants("Test")
                   .Select(x => TestClass.FromXElement(x))
                   .ToList();
    

    Where TestClass.FromXElement is something like:

    public static TestClass FromXElement(XElement element)
    {
        string name = (string) element.Element("Name");
        string type  = (string) element.Element("Type");
        List<string> members = element.Descendants("Member")
                                      .Select(x => x.Value)
                                      .ToList();
        return new TestClass(name, type, members);
    }
    

    (You don’t have to use Descendants if you’re rather control the hierarchy more strictly. For example, in TestClass.FromXElement you could use element.Element("Members").Elements("Member")

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