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Asked: 2026-06-13T03:03:44+00:00

I have a XSL that transforms one format of XML into another. In input

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I have a XSL that transforms one format of XML into another. In input XML I have a node with following value – which is actually a XML string if we replace &lt; with < (less than) for e.g.

<otherInfo>&amp;lt;Paragraph&amp;gt;&amp;lt;Title&amp;gt;&amp;lt;!CDATA[Pour les nuits du 2012-10-01 - 2012-10-30]]&amp;gt;&amp;lt;/Title&amp;gt;&amp;lt;Text&amp;gt;&amp;lt;![CDATA[TAXES INCLUSES.]]&amp;gt;&amp;lt;/Text&amp;gt;&amp;lt;/Paragraph&amp;gt;</otherInfo>

I want to have the content of otherInfo as a XML node in output XML.

if I do xsl:valueof select=”otherInfo”, I do not get it as a XML node – it is output just as text. How can I make XSL output the content of otherInfo as XML node ?

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1 Answer

  1. Editorial Team

    You either need to implement an XML parser written in XSLT, call an extension function, or wait for XSLT 3.0 where there may be a standard parse-xml() function.

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