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Home/ Questions/Q 6796475
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T18:29:37+00:00 2026-05-26T18:29:37+00:00

I have a yaml file which looks like this: — date: 25-01-2010 version: 0.1

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I have a yaml file which looks like this:

---
date: 25-01-2010
version: 0.1

I want to edit it. I using this code:

use YAML::XS qw(LoadFile);
use YAML::Syck qw(Dump);    

my $list = LoadFile("config.yaml");
$list{date} = "12-11-2011";
print "The date is $list->{date} \n";
print "The version is $list->{version} \n";
open F, '>', "config.yaml";
print F Dump( \%list );
close F;
}

and when it’s done my yaml file contains only date and empty line in the end.

--- 
date: 12-11-2011

What’s wrong with this code? if I checking value version before writing I getting good result, it’s showing version but it doesn’t write it at all…

I tried to use YAML::Syck::DumbFile but file after writing wasnt contain version too, and it was look like this :

---
date:
12-11-2011
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T18:29:38+00:00Added an answer on May 26, 2026 at 6:29 pm

    You are loading the YAML into $list. Then, you are setting 'date' in the hash %list (a completely different variable, which is initialized empty), and dumping that.

    ${$list}{date} = '12-11-2011';
    print Dump($list);
    

    You should read perlreftut and

    use strict;

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