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Home/ Questions/Q 1072665
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:53:32+00:00 2026-05-16T20:53:32+00:00

I have a zip file. I need a simple way to read the name

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I have a zip file.
I need a simple way to read the name of the files from the zip and read the contents of one of the files.

Can this be done directly in memory without saving,opening and reading the files ?

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  1. Editorial Team
    Editorial Team
    2026-05-16T20:53:34+00:00Added an answer on May 16, 2026 at 8:53 pm

    You need to open the archive and then can iterate over the files by index:

    $zip = new ZipArchive();
    if ($zip->open('archive.zip'))
    {
         for($i = 0; $i < $zip->numFiles; $i++)
         {  
              echo 'Filename: ' . $zip->getNameIndex($i) . '<br />';
         }
    }
    else
    {
         echo 'Error reading .zip!';
    }
    

    To read the content of a single file you can use ZipArchive::getStream($name).

    $zip = new ZipArchive();
    $zip->open("archive.zip");
    $fstream = $zip->getStream("index.txt");
    if(!$fp) exit("failed\n");
    
    while (!feof($fp)) {
        $contents .= fread($fp, 2);
    }
    

    Another way to directly do it is using the zip:// stream wrapper:

    $file = fopen('zip://' . dirname(__FILE__) . '/test.zip#test', 'r');
    ...
    
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