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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T17:16:31+00:00 2026-05-20T17:16:31+00:00

I have a Zip that contains two files: an XML and a thumbnail. I

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I have a Zip that contains two files: an XML and a thumbnail. I would like to open the XML file and parse it WITHOUT having to extract on disk.

One of DocumentBuilder’s parse method requires an InputStream. Is there a way to get the InputStream of the XML in the Zipped file? I kinda got lost. I’m pretty sure ZipInputStream or ZipFile has something to offer, but I can’t figure it out :/

Thank you in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-20T17:16:32+00:00Added an answer on May 20, 2026 at 5:16 pm

    I believe you’re looking for something like this:

    FileInputStream fin = new FileInputStream("your.zip");
    ZipInputStream zin = new ZipInputStream(fin);
    ZipEntry ze = null;
    while ((ze = zin.getNextEntry()) != null) {
        if (ze.getName().equals("your.xml")) {
            // pass zin to DocumentBuilder
        }
    }
    
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