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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T11:49:17+00:00 2026-06-13T11:49:17+00:00

I have about 1500 items in an Open Office CSV file like this: <a

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I have about 1500 items in an Open Office CSV file like this:

<a href=\http://localhost:81/rare_posts/?attachment_id=9044\"><img class=\"alignright size-medium wp-image-9044\" title=\"200064 British medical association\" src=\"http://localhost:81/books_posts/wp-content/uploads/British-medical-association-300x202.jpg\" alt=\"\" width=\"300\" height=\"202\" /></a>

What I need to do is find just the image (British-medical-association-300×202.jpg) and place this into the next cell. I am assuming there must be some way for me to run a command in Open Office to find all instances of uploads/, the point where we start stripping out all the text after this point and stop at .jpg?

Many thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-13T11:49:18+00:00Added an answer on June 13, 2026 at 11:49 am

    OpenOffice has no formula function to return a match by a regex. It does support regex search if you enable regular expressions in the options.

    You can go with two formulas to extract one occurence per cell (without using a regex search). One to find the left end and one to find the right end:

    Assuming the data is in A1

    B1   =MID(A1;FIND("uploads/";A1)+8;LEN(A1))
    C1   =LEFT(B1;FIND("\";B1)-1)
    

    If you have more than one occurence per cell, you can clone the formulas and supply the first FIND a third parameter, where to start searching (past the first occurence).

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