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Home/ Questions/Q 8846837
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T12:05:51+00:00 2026-06-14T12:05:51+00:00

I have allready compiled a few tiny programms in java and everything was fine.

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I have allready compiled a few tiny programms in java and everything was fine. But my new code has any problem.

class myclass
{
 public static void main (String[] args)
 {
  int x, y;
  String s ="sssss";
  x=args.length;
  s= args[0].substring(1,2);
  System.out.println("Num of args: "+x);
  System.out.println("List of args:");
  y = parseInt(s,5);
  }
}

The compiler says:

 e:\java\4>javac myclass.java 
  myclass.java:11: error: cannot find symbol   
   y = parseInt(s,5);
       ^   symbol:   method parseInt(String,int)   location: class myclass 1 error

 e:\java\4>

The strange thing is that the compiler jumps over the method substring (as there is no problem) but the method parseInt seems to have any problem.
y = parseInt(s); OR: y = parseInt(“Hello”); –> Also the same compiler message.

Or does the method not exist? docs.oracle–>Integer says it exists 🙂

It makes my really crazy as i don’t know how to search for the error. I have checked the internet allready, i checked the classpath and the path…

So it would be great if any expert could help me. 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T12:05:51+00:00Added an answer on June 14, 2026 at 12:05 pm

    parseInt is a static method in Integer class. you need to call it like this:

      y = Integer.parseInt(s,5);
    
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