Question

I have already looked at this question but there was no solution.
Here is the problem.

po [myNumberFormatter stringFromNumber:myNumber]

Output–> (id) $4 = 1.500,00

p (char) [(NSString *)[myNumberFormatter stringFromNumber:myNumber] characterAtIndex:1]

Output–> (char) $5 = ‘\xa0’

po [(NSString *)[myNumberFormatter stringFromNumber:myNumber] stringByReplacingOccurrencesOfString:@"\xa0" withString:@" "]

Output–> (id) $6 = 1.500,00

One thing to note though is that on the screen, the value 1.500,00 looks like 1 500,00.
But is there any way to convert the ‘\xa0’ character to a @" " within the string?

This following solution already works, but it has the problem of converting everything not included into a blank character.

po [(NSString *)[myNumberFormatter stringFromNumber:myNumber] stringByReplacingSequenceOfCharactersInSet:(NSCharacterSet *)[[NSCharacterSet characterSetWithCharactersInString:@"0123456789,."] invertedSet] with:@" "]

Edit ————–

I’ve tried the answer below and i thought it was wrong becuase

po [(NSString *)[numberFormatter stringFromNumber:theNumber] stringByReplacingOccurrencesOfString:@"\u00a0" withString:@" "] 

still produced the same result (the \xa0 char was still not removed). But when I did not place it in the debugger, but instead placed it in a NSString within the code, the correct answer was stored and the \xa0 character was removed. Guess I should not depend on debugger log alone.

Answer 1

NSString *str = // string to cleanup
str = [str stringByReplacingOccurrencesOfString:@"\u00a0" withString:@" "];

The \u00a0 will get replaced at compile time with an actual no-break space.