Question

I have already read throw the suggestions on Converting Double to String in C++ and
Convert double to string C++?
but I have been asked to create a function non-OOP to take in a double, and return a std::string using only math. I have been able to do this with an int in the past wich:

std::string toString(int value) {
    string result = "";
    bool negative = false;
    if ( value < 0 ) {
        negative = true;
        value *= (-1);
    }
    do {
        string tmpstr = "0";
        tmpstr[0] += value%10;
        result = tmpstr + result;
        value /= 10;
    } while ( value != 0);
    if ( negative ) {
        result = "-" + result;
    }
    return result;
}

but the problem is that it uses a check for greater then zero to keep going. I keep thinking something like

if ( value < 0 ){
    value *= 10;
}

I thing that this should go before the %10 but I’m not sure. every time I try I get a whole number, and not the decimal.

for example I give it 125.5 (result of 251/2), and it outputs 1255. though in some cases I only get 125. any help would be great.

Update:chosen solution

std::string toString(float value){
    bool negative = false;
    if ( value < 0 ) {
        negative = true;
        value *= (-1);
    }

    int v1 = value;         // get the whole part
    value -= v1;            // get the decimal/fractional part
    //convert and keep the whole number part
    std::string str1 = toString(v1); 

    std::string result = "";
    do {
        value *= 10;
        int tmpint = value;
        value -= tmpint;
        string tmpstr = "0";
        tmpstr[0] += tmpint % 10;
        result = tmpstr + result;
        value /= 10;
    } while ( value != 0);

    result = str1 + "." + result;

    if ( negative ) {
        result = "-" + result;
    }
    return result;
}

Answer 1

Do you have to use math, can’t you use an ostringstream?

Otherwise you can do it in two parts:

1. First get the integer part.
2. Then get the fraction part.

To get the integer part, just cast the value to an int. To get the fraction part by itself, subtract the integer part from value.

When you have the fractions, multiply by ten and get the that value as an integer, which will be a single-digit integer.

Edit: Added code sample

#include <string>
#include <algorithm>   // for std::reverse
#include <cmath>       // for std::fabs

// ...

std::string toString(double value)
{
    // Get the non-fraction part
    int ival = int(value);

    // Get the fraction part
    double frac = std::fabs(value - ival);

    // The output string
    std::string str;

    // Is the number negative?
    bool negative = false;

    // Convert the non-fraction part to a string
    if (ival < 0)
    {
        negative = true;
        ival = -ival;
    }

    while (ival > 0)
    {
        str += char((ival % 10) + '0');
        ival /= 10;
    }

    // The integer part is added in reverse, so reverse the string to get it right
    std::reverse(str.begin(), str.end());

    if (negative)
        str = std::string("-") + str;

    if (frac > 0.0)
    {
        str += '.';

        // Convert the fraction part
        do
        {
            frac *= 10;
            ival  = int(frac);
            str  += char(ival + '0');
            frac -= ival;
        } while (frac > 0.0);
    }

    return str;
}

Note: The above function exposes some of the problems floating point numbers have on computers. For example, the value 1.234 becomes the string "1.2339999999999999857891452847979962825775146484375".