Question

I have an activity in which I display an image that is stored on a website.
I am using the following code to get it from its url and display the activity :

public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    Log.i(TAG, "onCreate");
    setContentView(R.layout.ad_screen);

    AsyncTask<String, Void, Integer> task = new AsyncTask<String, Void, Integer>() 
    {
        /** The system calls this to perform work in a worker thread and
         * delivers it the parameters given to AsyncTask.execute() */
        @Override
        protected Integer doInBackground(String... urls) 
        {
            fetchAd();
            return 0; 
        }

        /** The system calls this to perform work in the UI thread and delivers
         * the result from doInBackground() */
        @Override
        protected void onPostExecute(Integer result) 
        {
            displayAd();
        }
    };
    task.execute("");
}

That works very fine, but the behaviour is not the one I want : in this case, the activity is pushed on the screen (with a right to left animation) and then the AsyncTask begins. So the image is displayed on screen after a delay (which is normal).

But I would like to perform the request before the activity is pushed, so that the screen is displayed directly with its image without any delay.

Is there a way to have this behaviour ?
Thanks in advance.

Answer 1

You can download the image in the previous activity, create a bitmap, then pass it as an extra in the intent that launches this activity.