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Home/ Questions/Q 604119
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:00:15+00:00 2026-05-13T17:00:15+00:00

I have an Address column in a table that I need to split into

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I have an Address column in a table that I need to split into multiple columns in a view in SQL Server 2005. I need to split the column on the line feed character, chr(10), and there could be from 1 to 4 lines (0 to 3 line feeds) in the column. Below are a couple of examples of what I need to do. What is the simplest way to make this happen?

Examples:

Address                 Address1      Address2       Address3            Address4
------------        =   -----------   -----------    -----------------   ---------
My Company              My Company     123 Main St.  Somewhere,NY 12345  
123 Main St.         
Somewhere,NY 12345

Address                 Address1       Address2      Address3      Address4
------------        =   ------------   ----------    -----------   ---------
123 Main St.            123 Main St.
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  1. Editorial Team
    Editorial Team
    2026-05-13T17:00:15+00:00Added an answer on May 13, 2026 at 5:00 pm

    this will split the address by using the parsename function and combining that with COALESCE to grab the correct info in the correct column

    if you have more than 4 lines this method will NOT work

    edit: added the code to reverse the order

        create table #test (address varchar(1000))
    
        --test data
        insert #test values('My Company
        123 Main St.         
        Somewhere,NY 12345')
    
        insert #test values('My Company2
        666 Main St.  
        Bla Bla       
        Somewhere,NY 12345')
    
        insert #test values('My Company2')
    
        --split happens here
                                select
    replace(parsename(address,ParseLen +1),'^','') as Address1,
    replace(parsename(address,ParseLen ),'^','') as Address2,
    replace(parsename(address,ParseLen -1),'^','') as Address3,
    replace(parsename(address,ParseLen -2),'^','') as Address4
    from(
    select case  ascii(right(address,1)) when 10 then
    replace(replace(left(address,(len(address)-1)),'.','^'),char(10),'.')  
    else 
    replace(replace(address,'.','^'),char(10),'.') end as address,
    case  ascii(right(address,1)) when 10 then
    len(replace(replace(address,'.','^'),char(10),'.')) -
    len(replace(replace(address,'.','^'),char(10),'')) -1
    else
    len(replace(replace(address,'.','^'),char(10),'.')) -
    len(replace(replace(address,'.','^'),char(10),'')) end as ParseLen
     from #test) x
    
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