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Home/ Questions/Q 486457
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T01:30:19+00:00 2026-05-13T01:30:19+00:00

I have an AIR application with a system tray icon. When clicked it shows

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I have an AIR application with a system tray icon. When clicked it shows and activates the app. This is working as expected when the app is hidden (docked), however if I select another application so my app is in the background clicking on the system tray icon does nothing.

Oddly I also have a contextual menu on the system tray icon, which has an option to restore, this calls the same event handler as ScreenMouseEvent.CLICK, yet works.

I expect it’s something to do with the contextual menu changing the focus, perhaps it’s a bug in how AIR works with the system tray, perhaps it’s just something I’m missing. Would be good to know if that’s the case.

Thanks in advance

Rob

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  1. Editorial Team
    Editorial Team
    2026-05-13T01:30:19+00:00Added an answer on May 13, 2026 at 1:30 am
    //instead of just calling
    activate();
    
    //call
    nativeApplication.activate()
    
    //or even better
    nativeApplication.activate(nativeWindow);
    

    Update based on OP’s input: if you have multiple windows open for the application, use:

    nativeApplication.activate(nativeApplication.openedWindows[0]);
    

    If you are not in the main WindowedApplication class, you can use the static property NativeApplication.nativeApplication to get a reference to the singleton object.

    WindowedApplication.activate()

    Activates the underlying NativeWindow (even if this application is not the active one).

    NativeApplication.activate(window:NativeWindow = null)

    Activates this application. If the operating system allows activation, then the specified window is activated and brought to the desktop foreground; that is, in front of the windows of other applications. (If the window parameter is null, then a visible window of this application is activated.)

    livedocs is not clear on why this is happening. It says activate() activates the underlying native window – one would expect it to be brought to the front when it is activated, but that’s not happening.

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