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Home/ Questions/Q 3314152
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:11:53+00:00 2026-05-17T22:11:53+00:00

I have an ajax call that returns a HTML fragment. I am trying to

  • 0

I have an ajax call that returns a HTML fragment. I am trying to select a div in that fragment before rendering.

An example of the HTML:

<div class="event-detail repBy-container">
    <div class="copy">.....</div>
    <div class="links">
       ....
    </div>
    <div class="contacts">
      <div class="name-brand">....</div><div class="details">...., <a href="mailto:...@....">...</a></div>
    </div>
</div>

Now the problem:

function ajaxReturn(data) {
   alert($(data).find('.event-detail').length); <-- Returns 0
   alert($(data).find('.copy').length); <-- Returns 1
}

Is this a bug or am I doing something wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:11:54+00:00Added an answer on May 17, 2026 at 10:11 pm

    .find() gets descendants only, not from the current level, you’d need .filter() to get items from the current set (which is the root of what you returned), like this:

    function ajaxReturn(data) {
       alert($(data).filter('.event-detail').length); //<-- Returns 1
       alert($(data).find('.copy').length); //<-- Returns 1
    }
    

    If you want .find() to work in both cases, add the content to a parent container, like this:

    function ajaxReturn(data) {
       var parent = $("<div />").append(data);
       alert(parent.filter('.event-detail').length); //<-- Returns 1
       alert(parent.find('.copy').length); //<-- Returns 1
    }
    
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