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Home/ Questions/Q 217635
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T18:40:33+00:00 2026-05-11T18:40:33+00:00

I have an ajax form in asp.net mvc which is as simple as this:

  • 0

I have an ajax form in asp.net mvc which is as simple as this:


    <% using (this.Ajax.BeginForm("LatestBlogPosts", "Blog", null, new AjaxOptions { UpdateTargetId = "blogPostPanel" }, new { id = "BlogPostForm" })) { %>
    <div class="panel" id="blogPostPanel">
        <img src="/images/ajax-loader.gif" alt="ajax-loader" />
    </div>
    <% } %>

I want to invoke the form submit when document is loaded. This should supposedly, call the controller’s action and return a result that should be replaced with the placeholder DIV. If I add a SUBMIT button to the form, it works perfectly, but when I invoke the submit via jQuery, the whole page is refreshed, and the content returned by the server is displayed in the newly displayed page. Here’s my jQuery code:


    <script type="text/javascript">
        $(document).ready(function() {
            $("#BlogPostForm").submit();
        });
    </script>

Anyway to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-11T18:40:33+00:00Added an answer on May 11, 2026 at 6:40 pm

    I think it may work if you use the trigger method to generate the submit event, but I think there’s a less complicated way to do this using jQuery.

    <div class="panel" id="blogPostPanel">
        <img src="/images/ajax-loader.gif" alt="ajax-loader" />
    </div>
    
    <script type="text/javascript">
        $(function() {
             $('#blogPostPanel').load( '<%= Url.Action( "LatestBlogPosts", "Blog" ) %>' );
        });
    </script>
    
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