I have an almost working solution. However, it fails to compile some simple cases, and I can’t decipher the error message.
My current solution:
#define AUTO_RETURN( EXPR ) -> decltype( EXPR ) \
{ return EXPR; }
template< typename BinaryFunc, typename First, typename Second >
auto foldl( BinaryFunc&& func, First&& first, Second&& second )
AUTO_RETURN( func( std::forward<First>(first), std::forward<Second>(second) ) )
template<typename BinaryFunc, typename First, typename Second, typename... Rest >
auto foldl( BinaryFunc&& func, First&& first, Second&& second, Rest&&... rest )
AUTO_RETURN(
foldl(
std::forward<BinaryFunc>(func),
func( std::forward<First>(first), std::forward<Second>(second) ),
std::forward<Rest>(rest)... )
)
This works as expected:
struct adder
{
template< int LHS, int RHS >
std::integral_constant<int,LHS+RHS>
operator()( std::integral_constant<int,LHS>, std::integral_constant<int,RHS> )
{
return {};
}
};
auto result = foldl( adder(),
std::integral_constant<int,19>{},
std::integral_constant<int,23>{}
);
assert( result.value == 42 );
However this fails to compile.
foldl( adder(),
std::integral_constant<int,1>{},
std::integral_constant<int,2>{},
std::integral_constant<int,3>{},
std::integral_constant<int,4>{},
);
Oddly, if I remove all std::forward and rvalue refs from the code it works fine.
What am I doing wrong?
Is this a compiler bug?
The problem is that the
decltypein the return type of the variadicfoldlcannot see the variadicfoldl, as it hasn’t been fully declared yet, so it cannot recurse to another instantiation of itself.You can do it with a helper
struct: