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Home/ Questions/Q 6869805
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:36:15+00:00 2026-05-27T03:36:15+00:00

I have an ant script that compile my program, build the jar and then

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I have an ant script that compile my program, build the jar and then run it. My program takes one argument that is a file.

In my run target I would like to be able to execute my jar with all the files that are in a specified folder, one by one, as argument.

Do I have to write all the different cases by hand like:

<target name="run" depends="jar">
     <mkdir dir="${output.dir}" />
     <java jar="${myjar}.jar" output="${output.dir}/${test1}" fork="true">
          <arg value="${test.dir}/${test1}" />
     </java>
     <java jar="${myjar}.jar" output="${output.dir}/${test2}" fork="true">
          <arg value="${test.dir}/${test2}" />
     </java>

     #and so on

</target>

or is there a way to maybe iterate over my test directory and save me the writing of 20 other cases?

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:36:16+00:00Added an answer on May 27, 2026 at 3:36 am

    I found my solution using the <apply> tag (doc).

    My script looks like it now and every execution is outputted in separate files thanks to the <redirector> tag:

    <target name="run" depends="jar">
        <mkdir dir="${output.dir}" />
        <apply executable="java">
             <fileset dir="${test.dir}" />
             <arg value="-jar"/>
             <arg path="${jar.dir}/${myjar}.jar" />
             <srcfile />
             <redirector>
                  <outputmapper id="out" type="glob" from="*" to="${output.dir}/*" />
             </redirector>
        </apply>
    </target>
    
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