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Home/ Questions/Q 8709583
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:23:50+00:00 2026-06-13T04:23:50+00:00

I have an app I am writing for iOS and Android. On startup I

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I have an app I am writing for iOS and Android. On startup I am trying to get a random number between 1 and 6.

iOS (Objective-C):

int random = rand() % (6 - 1) + 1;

Android (Java):

Random random = new Random();
int num = random.nextInt(6)+1;

In both cases they return 3 every time.

From other questions I have read, people are having the same issue because they are looping through randoms and keep reinstantiating the Random object. But I just want one random number, so I am only instantiating it once.

So, how can I get either of these pieces of code to get a number 1-6 instead of just 3?

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:23:51+00:00Added an answer on June 13, 2026 at 4:23 am

    For the Objective-C part, I can tell you that you have to seed the random, like this:

    srand(time(0)); // seed it using the current time
    

    And for the Java part, the new Random() constructor automatically seeds it in the default JVM for desktop applications, but not on Android. On Android, it uses a default seed value.

    Random rand = new Random(System.nanoTime());
    
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