Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7843333
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T16:31:30+00:00 2026-06-02T16:31:30+00:00

I have an app which allows users to vote and have two tables Video

  • 0

I have an app which allows users to vote and have two tables

Video

|id|uri_code|filename|created_on|deleted|

Votes

|id|video_id|ip|created_on|

I’d like to be able to select all the video information and have the total number of votes for each video, is this possible with an sql statement or would I be best off doing it with the server side code?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-02T16:31:32+00:00Added an answer on June 2, 2026 at 4:31 pm

    It’s certainly possible with SQL – this sort of thing is exactly what SQL is great at! You want to “group” a count of all votes by video, so the GROUP BY clause is exactly what you’re after:

    SELECT Video.*, COUNT(*)
    FROM Video JOIN Votes ON Votes.video_id = Video.id
    GROUP BY Video.id;
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have created an app which allows users to buy non-consumable content. The retrieving-ids-payment-process
I have created an app which allows users to buy non-consumable content. The retrieving-ids-payment-process
I have a web app(jsp/servlets) which allows users to download audio files and play
I have a Rails app which allows users to upload Excel files which need
We have an ASP.NET MVC web app which allows users to publish messages onto
I have an app which allows users to log in via Facebook, and all
I am developing an app which allows users to color the images. I have
I have a small APP which allows users to view information on Beers and
I have a flex app which allows user to create some content. this content
So I'm making a Rails app which allows Users to create Items, and each

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.