Question

i have an application, and in my urls.py i have something like that:

      urlpatterns = patterns('',
                    url(r'^profile_view/(?P<id>\d+)/$', 
                       profile_view,
                       name='profile_view'),)

meaning that the profile_view function has id as a parameter.
Now, i want to call that function from my template, using a link like Reply

The problem is that i don’t know how to use the above url as a link, meaning how can i ‘pass the id parameter to a link’?
thank you

Answer 1

edit:

In your template you should have an object available via your view that holds all of the ids to your blog posts. Then you would simply loop through those to display links for each

{% for entry in blog_list %}
    <a href="yoururl.com/profile_view/{{ entry.id }}">{{ entry.name }}</a>
{% endfor %}